问题描述： 1、数学计算题,要过程,一定会采纳~ 1个回答 分类：数学 2014-10-01 问题解答： 我来补答 原式=（x-6y)/[(x+2y)(x-2y)]+2y/[x(x-2y]=[x(x-6y)/[x(x+2y)(x-2y)]+[2y(x+2y)]/[x(x+2y)(x-2y)]=[x²-6xy+2xy+4y²]/[x(x+2y)(x-2y)]=(x²-4xy+4y²)/[x(x+2y)(x-2y)]=(x-2y)²/[x(x+2y)(x-2y)]=(x-2y)/[x(x+2y)] 展开全文阅读
