问题描述: 计算(1-(2²分之1))(1-(3²分之1))(1-(4²分之1))···(1-(2013²分之1)) 1个回答 分类:综合 2014-12-04 问题解答: 我来补答 (1-1/2²)(1-1/3²)(1-1/4²)...(1-1/2013²)=(1+1/2)(1-1/2)(1+1/3)(1-1/3)(1+1/4)(1-1/4)...(1+1/2013)(1-1/2013)=(3/2)(1/2)(4/3)(2/3)(5/4)(3/4)...(2014/2013)(2012/2013)=[(3/2)(4/3)(5/4)...(2014/2013)][(1/2)(2/3)(3/4)...(2012/2013)]=[(3×4×5×...×2014)/(2×3×4×...×2013)][(1×2×3×...×2012)/(2×3×4×...×2013)]=(2013/2)(1/2012)=2013/4024 展开全文阅读