先化简,后求值：（x分之x-1-X+1分之X-2）除以x的平方+2x+1分之2x的平方-x

[（x-1)/x-(x-2)/(x+1)]÷[(2x^2-x)/(x^2+2x+1)]
=[(x-1)(x+1)-x(x-2)]/x(x+1)÷[x(2x-1)/(x+1)^2
=(2x-1)/x(x+1)×（x+1)^2/x(2x-1)
=(x+1)/x^2