问题描述:
(³√-216+√2+1/4+³√64)×√(-0.1²)/1= (-2)³×√(-4)³+³√(
(³√-216+√2+1/4+³√64)×√(-0.1²)/1=
(-2)³×√(-4)³+³√(-4)³×(-1/2)²-³√27=
求解
(³√-216+√2+1/4+³√64)×√(-0.1²)/1=
(-2)³×√(-4)³+³√(-4)³×(-1/2)²-³√27=
求解
问题解答:
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