解方程组:x+2y+z=10,2x+3y-z=3,3x+2y+2z=17

x+2y+z=10(1)
2x+3y-z=3(2)
3x+2y+2z=17(3)
(1)+(2)得3x+5y=13(4)
2(2)+(3)得7x+8y=23(5)
(4)和(5)得21x+35y=91(6)
21x+24y=69(7)
(6)-(7)得11y=22,所以y=2
y=2代入（4）得y=2
x=1,y=2代入（1）得z=5
所以解得x=1,y=2,z=5