计算:8(72+1)(74+1)(78+1)(716+1)(732+1).

问题描述:

计算:8(72+1)(74+1)(78+1)(716+1)(732+1).
1个回答 分类:数学 2014-12-01

问题解答:

我来补答
原式=
(7+1)(7−1)(72+1)
6•(74+1)(716+1)(78+1)
=
1
6(72-1)(72+1)(74+1)(78+1)(716+1)(732+1)
=
1
6(74-1))(74+1)(78+1)(716+1)(732+1)
=
1
6(78-1)(78+1)(716+1)(732+1)
=
1
6(716-1)(716+1)(732+1)
=
1
6(732-1)(732+1)
=
1
6(764-1).
 
 
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