问题描述: 计算:8(72+1)(74+1)(78+1)(716+1)(732+1). 1个回答 分类:数学 2014-12-01 问题解答: 我来补答 原式=(7+1)(7−1)(72+1)6•(74+1)(716+1)(78+1)=16(72-1)(72+1)(74+1)(78+1)(716+1)(732+1)=16(74-1))(74+1)(78+1)(716+1)(732+1)=16(78-1)(78+1)(716+1)(732+1)=16(716-1)(716+1)(732+1)=16(732-1)(732+1)=16(764-1). 展开全文阅读