问题描述: 高一三角函数化简 sin^2(α)/((sinα)-(cosα))+(cosα)/(1-tan(α)) 1个回答 分类:数学 2014-11-21 问题解答: 我来补答 sin^2(α)/((sinα)-(cosα))+(cosα)/(1-tan(α)) = sin^2(α)/((sinα)-(cosα))+(cosα)/(1-sin(α)/cos(α)) =sin^2(α)/((sinα)-(cosα))+cos^2(α)/(cos(α)-sin(α)) =(sin^2(α)-cos^2(α))/((sinα)-(cosα)) =((sinα)-(cosα))((sinα)+(cosα))/((sinα)-(cosα)) =sinα+cosα 展开全文阅读