问题描述: (1-2^2/1)(1-3^2/1)(1-4^2/1)…(1-99^2/1)(1-100^2/10) 简便方法计算 1个回答 分类:数学 2014-10-20 问题解答: 我来补答 题目应是(1-2^2/1)(1-3^2/1)(1-4^2/1)…(1-99^2/1)(1-100^2/1) =(1-2/1)(1+2/1)(1-3/1)(1+3/1).(1-99/1)(1+99/1)(1-100/1)(1+100/1)=(1-2/1)(1-3/1).(1-99/1)(1-100/1)(1+2/1)(1+3/1).(1+99/1)(1+100/1)=(2/1)(3/2).(99/98)(100/99) (2/3)(3/4).(99/100)(100/101)=(100/1) (2/101)=200/101 展开全文阅读