(a2-1)^3+2010(a2-1)=1
(a(2009)-1)^3+2010(a(2009)-1)=-1
(a(2009)+a2-2)[(a(2009)-1)^2-(a(2009)-1)(a2-1)+(a2-1)^2]=0
若(a(2009)-1)^2-a(2009)-1)(a2-1)+(a2-1)^2=(a(2009)-1/2*a2-1/2)^2+3/4 *(a2-1)^2=0
a2=1,a2009=1,不符合题意
故a2+a(2009)=2
S2010=(a1+a(2010))+(a2+a(2009))+...=1005*2=2010故2是正确的.
f(x)=(x-1)^3+2010(x-1)
f(1)=0,f(2)>>1
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