问题描述：
fortran的3个简单语句,有谁会fortran的解释下
do i = 1,n
z(i) = x(i) + y(i)
enddo
do i = 2,n
z(i) = z(i - 1)*2
enddo
do i = 2,n
z(i) = z(1)*2**(i - 1)
enddo
do i = 1,n
z(i) = x(i) + y(i)
enddo
do i = 2,n
z(i) = z(i - 1)*2
enddo
do i = 2,n
z(i) = z(1)*2**(i - 1)
enddo
问题解答：
我来补答展开全文阅读