问题描述: y=f(x^2+1),且f'(x)=x^2,则dy/dx | x=-1=? 1个回答 分类:数学 2014-12-16 问题解答: 我来补答 df(x)/dx = x^2,df(x^2+1)/d(x^2+1) = (x^2+1)^2,dy/dx = df(x^2+1)/dx = df(x^2+1)/d(x^2+1)*d(x^2+1)/dx = (x^2+1)^2* 2x,dy/dx|_{x=-1} = [2x(x^2+1)^2]|_{x=-1}=[2(-1)(1+1)^2]=-8 展开全文阅读