问题描述:
(1+1/1997+1/1999+1/2001)×(1/1997+1/1999+1/2001+1/2003)-(1+1/1997+1/1999+1/2001+1/2003)×(1/1997+1/1999+1/2001)=[1+(1/1997+1/1999+1/2001)]×(1/1997+1/1999+1/2001+1/2003)-[1+(1/1997+1/1999+1/2001+1/2003)]×(1/1997+1/1999+1/2001)=1/1997+1/1999+1/2001+1/2003-1/1997-/1999-1/2001=1/2003
问题解答:
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