问题描述: 1、因式分解:(x+1)(2x-1)-(2x-1)^2 2、计算:[x(x^2y^2-xy)-y(x^2+x^3y)]÷3x^2y 1个回答 分类:数学 2014-11-10 问题解答: 我来补答 1、因式分(x+1)(2x-1)-(2x-1)^2=(2X-1)[(X+1)-(2X-1)]=-(2X-1)(X-2)2、计算:[x(x^2y^2-xy)-y(x^2+x^3y)]÷3x^2y=[X^2Y(XY-1)-X^2Y(1+XY)]÷3X^2Y=X^2Y(XY-1-1-XY)÷3X^2Y=-2/3 展开全文阅读