不等式1/2^x-1>1/1-2^x-1的解集为

1/(2^x -1)>1/(1- 2^(x-1))
令2^(x-1)=t,则2^x=2*2^(x-1)=2t
∴1/(2t-1)>1/(1-t)
1/(2t-1)+1/(t-1)>0
(3t-2)/[(2t-1)(t-1)]＞0
∴t＞1或t∈﹙1/2,2/3﹚
即2^(x-1）＞1或1/2＜2^(x-1）＜2/3
x-1＞0 or -1＜x-1＜log﹙2﹚﹙2／3﹚
即x＞1或0＜x＜1+log﹙2﹚﹙2／3﹚
亦即0＜x＜2-log﹙2﹚3或x＞1