问题描述: 三角形三个角比求出三边比 公式 1个回答 分类:数学 2014-10-26 问题解答: 我来补答 设三个角比为A:B:C = x:y:z.则,A = xt,B = yt,C = zt,其中,t为待定常数.因PI = A + B + C = t(x+y+z),t = PI/(x+y+z).A = xPI/(x+y+z),B = yPI/(x+y+z),C = zPI/(x+y+z).再利用正弦定理,a:b:c = sin(A):sin(B):sin(C) = sin[xPI/(x+y+z)] :sin[yPI/(x+y+z)] :sin[zPI/(x+y+z)] 展开全文阅读